pangkat2 integral -1 (3xpangkat2 +2x-10) dx

jawab


₋₁²∫ (3x² + 2x - 10) dx =

= [ x³ + x² -10x]²₋₁

= (2³-(-1)³) + (2² -(-1)²)  - 10( 2 -(-1))
= (8 + 1) + (4 - 1) - 10(2+1)
= 9 + 3 - 10
= 2