Hitunglah keliling dan luas segitiga ABC disamping!! Bantu ya guyss

AB² = BD x BC
= 9 x 13
= 117
AB = √117 = 3√13

AC² = CD x CB
= 4 x 13 = 52
AC = √52 = 2√13

Keliling = 3√13 + 2√13 + 13
= 13 + 5√13
Luas = (alas x tinggi)/2
= (2√13 x 3√13)/2
= 78 / 2
= 39 cm²