himpunan penyelesaian 8 pangkat 3x-4 >1/32 pangkat -x+2

[tex]8^{3x-4}\ \textgreater \ (\frac{1}{32})^{-x+2} \\ \\ 2^{3\cdot(3x-4)}\ \textgreater \ 2^{-5\cdot(-x+2)} \\ 3\cdot(3x-4)\ \textgreater \ -5\cdot(-x+2) \\ 9x-12\ \textgreater \ 5x-10 \\ 9x-5x\ \textgreater \ -10+12 \\ 4x\ \textgreater \ 2 \\ x\ \textgreater \ \frac{2}{4} \\ \\ x \ \textgreater \ \dfrac{1}{2}[/tex]