Matematika

Pertanyaan

3 log 2 = P dan 2 log 7 = Q maka 14 log 54 =

1 Jawaban

  • 3log2=p
    2log7=q
    3log7=pq
    14log54=3log54/3log14
    =3log27+3log2/3log7+3log2
    =3^1log3^3+3log2/3log7+3log2
    =3/1.3log3+3log2/3log7+3log2
    =3.1+p/pq+p
    =3+p/pq+p

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