luas daerah yang dibatasi kurva y=4-x² dan y=x+2

Matematika

y = 4 - x²
x + 2 = 4 - x²
x² + x - 2 = 0
(x - 1)(x + 2) = 0
x = 1 dan x = -2


L = - ( ¹ int -2 (x + 2 - (4 - x²)) )
L = - ( ¹ int -2 (x² + x - 2) )
L = - ( [⅓ x³ + ½ x² - 2x]¹ -2 )
L = - ( (⅓ .1³ + ½ .1² - 2.1) - (⅓ . (-2)³ + ½ .(-2)² - 2(-2)) )
L = ( (⅓ + ½ - 2) - ( - 8/3 + 2 + 4) )
L = - ( - 7/6 - 10/3 )
L = - ( - 7/6 - 20/6 )
L = 27/6
L = 9/2
L = 4 ½ satuan luas