Hitunglah integral 6 0 (5x^3 +6x^2 +4x +7) dx

.............6

Integral (5x^3 + 6x^2 + 4x + 7) dx

.............0

.......................................................6

= 5/4 x^4 + 2x^3 + 2x^2 + 7x |

.......................................................0

= [5/4 (6^4) + 2(6^3) + 2(6^2) + 7(6)] - [5/4 (0^4) + 2(0^3) + 2(0^2) + 7(0)]

= [5/4 (1296) + 2(216) + 2(36) + 42] - [5/4 (0) + 2(0) + 2(0) + 0]

= (1620 + 432 + 72 + 42) - (0 + 0 + 0 + 0)

= 2166 - 0

= 2166