| 3x-5| = |x+20| himpunan penyelesaian

[tex](3x - 5)^{2} = ( \times + 20) ^{2} \\ (3x - 5)^{2} - (x + 20)^{2} = 0 \\ ((3x - {5) - (x + 20))}((3x - 5) + (x + 20)) \\ (2x - 25)(4x + 15) = 0 \\ x1 = \frac{25}{2} \: \: \: \: \: \: atau \: x2 = \frac{ - 15}{4} [/tex]