Matematika

Pertanyaan

tolong nomor 29 & 30
tolong nomor 29 & 30

1 Jawaban

  • 29.
    Keliling = 2(p + l)
    32 = 2(3a + 3 + 2a - 2)
    32 = 2(5a + 1)
    32 = 10a + 2
    32 - 2 = 10a
    30 = 10a
    30 : 10 = a
    a = 3

    p = 3a + 3
    = 3(3) + 3
    = 9 + 3
    = 12 cm

    l = 2a - 2
    = 2(3) - 2
    = 6 - 2
    = 4 cm

    Luas = p × l
    = 12 × 4
    = 48 cm^2 (C)

    30.
    [tex]a = 2 {x}^{2} + 3 \\ b = 1 - {x}^{2} [/tex]
    [tex]2a + 3b \\ = 2(2 {x}^{2} + 3) + 3(1 - {x}^{2} ) \\ = 4 {x}^{2} + 6 + 3 - 3 {x}^{2} \\ = (4 {x}^{2} - 3 {x}^{2} ) + (6 + 3) \\ = {x}^{2} + 9[/tex]
    jawaban = B