Berapakah hasi dari Integral √x¹/² + 2x -5

[tex] \sqrt{ {x}^{ \frac{1}{2} } } \: + 2x + 5 \\ = {x}^{ \frac{1}{2} \div 2} + 2x + 5 \\ = {x}^{ \frac{1}{2} \times \frac{1}{2} } + 2x + 5 \\ = {x}^{ \frac{1}{4} } + 2x + 5 \\ = \frac{1}{4} {x}^{ \frac{1}{4} + 1} + \frac{2}{1 + 1} {x}^{1 + 1} + 5x + c \\ \frac{1}{4} {x}^{ \frac{5}{4} } + {x}^{2} + 5x + c[/tex]