jika 2log 3 =a dan 3log 5 =b maka 6log 15 =

³log 5 = b
²log 3 = a => ³log 2 = [tex] \frac{1}{a} [/tex]

[tex] ^6 \log 15 = \frac{ ^3 \log 15 }{^3 \log 6} \\
= \frac{ ^3 \log 5 \times 3 }{ ^3 \log 2 \times 3} \\
= \frac{ ^3 \log 5 + ^3 \log 3}{ ^3 \log 2 + ^3 \log 3} \\
= \frac{b + 1}{ \frac{1}{a} + 1} [/tex]