Nilai x yang memenuhi persamaan 1000^(x2-3x-4)=10^(x2-2x-3)

[tex] {1000}^{ {x}^{2} - 3x - 4 } = {10}^{ {x}^{2} - 2x - 3 } \\ {( {10}^{3}) }^{ {x}^{2} - 3x - 4 } = {10}^{{x}^{2} - 2x - 3} \\ {10}^{3 \times ( {x}^{2} - 3x - 4)} = {10}^{ {x}^{2} - 2x - 3} \\ {10}^{3 {x}^{2} - 9x - 12 } = {10}^{ {x}^{2} - 2x - 3 } \\ 3 {x}^{2} - 9x - 12 = {x}^{2} - 2x - 3 \\ 3 {x}^{2} - 9x - 12 - ( {x}^{2} - 2x - 3) = 0 \\ 3 {x}^{2} - 9x - 12 - {x}^{2} + 2x + 3 = 0 \\ (3 {x}^{2} - {x}^{2} ) + ( - 9x + 2x) + ( - 12 + 3) = 0 \\ 2 {x}^{2} - 7x - 9 = 0 \\ (2x - 9)(x + 1) = 0[/tex]
1.
2x - 9 = 0
2x = 9
x = 9 : 2
[tex]x = \frac{9}{2} [/tex]

2.
x + 1 = 0
x = -1