diketahui a=1,b=3,dan c=4 maka tentukan nilai dari (3a-c)(b-2c)!

(3a-c)(b-2c)
(3(1)-4)(3-2(4)
(3-4)(3-8)
(-1)(-5)
5

=(3×1-4)(3-2×4)
= (3-4)(3-8)
• 3 × 3 = 9
• 3×-8 = -24
• -4×3 = -12
• -4×-8= 32

= (9-24)(-12+32)
= -15+20
= 5

#smoga membantu