sederhanakan bentuk bentuk aljabar berikut [tex] \frac{3b - bx}{cx - 3c} [/tex] yang jawab yang bisa aja ya...

[tex] \frac{3b - bx}{cx - 3c} = \frac{b.(3-x)}{c.(x-3)}= \frac{b(3-x)}{c.(-1).(3 - x)}= \frac{b}{-c} = -\frac{b}{c} [/tex]

[tex] \frac{3b - bx}{cx - 3c} \\ = \frac{b(3 - x)}{c(x - 3)} \\ = \frac{b( - (x - 3))}{c(x - 3)} \\ = \frac{b( - 1)}{c} \\ = \frac{ - b}{c} \\ = - \frac{b}{c} [/tex]

Semoga membantu..